שינויים

<math>int\frac{ln(x)-1}{ln(x)^2}dx=int\frac{ln(x)}{ln(x)^2}dx-int\frac{1}{ln(x)^2}dx =int\frac{1}{ln(x)}-int\frac{1}{ln(x)^2}={u=x,u`=1,v=frac{1}{ln(x)},v`=-frac{1}{xln(x)^2}=frac{x}{ln(x)}+int\frac{x}{xln(x)^2}-<<int\frac{1}{ln(x)^2}=frac{x}{ln(x)}</math>