שינויים

<math>\int\frac{\ln(x)-1}{\ln(x)^2}dx={\color{blue}\int\frac{dx}{\ln(x)}}-\int\frac{dx}{\ln(x)^2}={\color{blue}\frac{x}{\ln(x)}+\int\frac{dx}{\ln(x)^2}}-\int\frac{dx}{\ln(x)^2}</math> לבסוף: <math>\int\frac{\ln(x)-1}{\ln(x)^2}dx=\frac{x}{\ln(x)}+C</math>