שינויים

<math>\int \frac{ln(x)-1}{ln(x)^2} dx</math>

===פתרון===

<math>\int \frac {ln(x)-1}{ln(x)^2} dx=\int \frac {ln(x)}{ln(x)^2} dx - \int \frac {1}{ln(x)^2}dx =\int \frac {dx}{ln(x)}- \int \frac {dx}{ln(x)^2}</math>