שינויים

<math>B\cup C = \{x \; | \; x\in (A_1 \triangle A_2 \triangle \dots \triangle A_n ) \land x\not\in A_{n+1} \cup \{x \; | \; x \in A_{n+1} \land x\not\in (A_1 \triangle A_2 \triangle \dots \triangle A_n )\} = </math> <math>\{x \; | \; x\in \; \text{in odd number of sets from}\; A_1,A_2\dots A_n \land x\not\in A_{n+1} \cup \{x \; | \; x \in A_{n+1} \land x\not\in \text{in odd number of sets from}\; A_1,A_2\dots A_n \} = </math> <math>\{x \; | x\not\in A_{n+1} \land \; x\in \; \text{in odd number of sets from}\; A_1,A_2\dots A_n \cup \{x \; | \; x \in A_{n+1} \land x \in \text{in even number of sets from}\; A_1,A_2\dots A_n \}</math>